Divide the given polynomial by the given monomial

15 (a³b²c²– a²b³c² + a²b²c³) ÷ 3abc

In the given term

Dividend = 15 (a³b²c²– a²b³c² + a²b²c³)

Take out the common part in binomial term

= 3 × 5(a × a × a × b × b × c × c– a × a × b × b × b × c × c + a × a × b × b × c × c × c )

= 15 a²b²c²(a – b + c)

Divisor = 3abc

=

= 5abc[a-b + c]

= [5a²bc– 5ab²c + 5abc²]

Hence dividing 15 (a³b²c²– a²b³c² + a²b²c³) by 3abc gives out [5a²bc– 5ab²c + 5abc²]