Workout the following divisions:
11a3b3(7c – 35) ÷ 3a2b2(c – 5)
In the given term
Dividend = 11a3b3(7c – 35) ÷ 3a2b2(c – 5)
Take out the common part in binomial term
= 11 × a × a × a × b × b × b (7 × c - 5 × 7 )
= 11 × a × a × a × b × b × b × 7 (c - 5 )
= 77a3b3(c - 5)
Divisor = 3a2b2(c – 5)
= ![]()
=
ab
Hence dividing 11a3b3(7c – 35) by 3a2b2(c – 5) gives out
ab
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