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12. Factorisation
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Q2 of 105 Page 279

Divide the given polynomial by the given monomial

(5a3b – 7ab3) ÷ ab

In the given term


Dividend = (5a3b – 7ab3)


Take out the common part in binomial term


= (5 × a × a × a × b – 7 × a × b × b × b)


= ab(5a2 – 7b2)


Divisor = ab


=


= (5a2 – 7b2)


Hence dividing (5a3b – 7ab3) by ab gives out (5a2 – 7b2)


More from this chapter

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1

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2

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(3x2– 2x) ÷ x

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Questions · 105
12. Factorisation
1 1 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4 5 5 5 5 6 7 1 1 1 1 1 2 2 2 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
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