Q2 of 59 Page 7

Find the expansion of

(x + 5)(x – 3)(x – 1)

(x + 5)(x – 3)(x – 1)


Here the identity used is


(x + a)(x + b)(x + c) = x3 + (a + b + c) x2 + (ab + bc + ca)x + abc


(x + 5)(x – 3)(x – 1)


= x3 + (5 – 3 – 1) x2 + (5(– 3) + (– 3)(– 1)(– 1)5)x + 5(– 3)(– 1)


= x3 + x2 + (– 15 + 3 – 5) x + 15


= x3 + x2 – 17x + 15


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