The expansion of (x + 1)(x – 2)(x + 3) is
Using identity,
(x + a)(x + b)(x + c) = x3 + (a + b + c)x2 + (ab + bc + ca)x + abc
We have,
(x + 1)(x – 2)(x + 3) = x3 + (1 – 2 + 3)x2 + (– 2 – 6 + 3)x – 6
= x3 + 2x2 – 5x – 6
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