Q5 of 59 Page 23

If one of the factors of x2 – 6x – 16 is (x + 2) then other factor is

Let the other factor be (x + p)


Then, x2 – 6x – 16 = (x + p)(x + 2)


= x2 + (p + 2)x + 2p


On comparing the coefficients on both sides, we get,


p + 2 = – 6


⇒ p = – 8


∴ The other factor is (x – 8).

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