Q1 of 59 Page 10

Factorize the following expressions:

2a3 – 3a2b + 2a2c


= 2a3 – 3a2b + 2a2c
Highest common factor is a2

Taking a2 common in the term – 3a2b + 2a2c


we get,
=
2a3 + a2(– 3b + 2c)
Taking a2 common in both the terms
we get,


= a2(2a + (– 3b + 2c))
= a2(2a – 3a + 2c)
2a3 – 3a2b + 2a2c = a2(2a – 3a + 2c)


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