Q5 of 124 Page 29

Solve the following equations.

x + 2 log27 9 = 0

x + 2log279 = 0


⇒ x = - 2log279


⇒ x = log279 - 2


⇒ x = log33(32) - 2


⇒ x = log33(3) - 4


⇒ (33)x = 3 – 4


(∵ ax = b is the exponential form of logarithmic form of logab)


⇒ 3x = - 4 (compare the exponents)


⇒


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