Solve the equation in each of the following.

log2x + log4x + log8x =
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Here LHS is ![]()
⇒ log2x + log22x + log23x
⇒ ![]()
(∵
)
⇒ ![]()
(∵ logaMn = nlogaM)
⇒ ![]()
⇒ ![]()
⇒ ![]()
Now we equate LHS to the RHS i.e.
![]()
⇒ ![]()
⇒ logx2 = 1 or x1 = 2 or x = 2
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