log₁₀8 + log₁₀5– log₁₀4 =

Consider, log₁₀8 + log₁₀5– log₁₀4 = log₁₀(8× 5) – log₁₀4

(since, log_aM + log_aN = log_a(M× N) )

⇒ log₁₀8 + log₁₀5– log₁₀4 = log₁₀(40) – log₁₀4

= log₁₀(40 ÷ 4)

(since, log_aM – log_aN = log_a(M÷N) )

⇒ log₁₀8 + log₁₀5– log₁₀4 = log₁₀(10) = 1 (since, log_aa = 1)

Thus, correct answer is (C)