Prove the following equations.
log1012500 = 2 + 3log105
log1012500 = 2 + 3log105 = 2log1010 + 3log105
Let us consider the RHS:
i.e. 2 + 3log105 = 2log1010 + 3log105
= log10102 + log1053
(∵ logaMn = nlogaM)
= log10(102×53)
(∵ loga(M×N) = (logaM) + (logaN))
= log10(100×125)
= log10(12500)
Hence LHS = RHS
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