Evaluate:

log₃ 7

Let log₃ 7 = log₁₀7× log₃10

(since, log_aM = log_bM × log_ab)

Then

Taking log on both side

⇒ log x = log 0.8450 – log 0.4771

(∵ log a÷ b = loga – log b)

⇒ log x = –0.0731– (–0.3213)

= – 0.0731 + 0.3213

= 0.2482

⇒ x = antilog 0.2482 = 1.771