Prove the following equations.
log101600 = 2 + 4log102
log101600 = 2 + 4log102 = 2log1010 + 4log102
Let us consider the RHS:
i.e. 2 + 4log102 = 2log1010 + 4log102
(∵ logaa = 1)
= log10102 + log1024
(∵ logaMn = nlogaM)
= log10100 + log1016
= log10(100×16)
(∵ loga(M×N) = (logaM) + (logaN))
= log101600
Hence LHS = RHS
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