Q9 of 65 Page 139

Let us factorize the following algebraic expressions:

8a3 – b3 – 4ax + 2bx

Given,


8a3 – b3 – 4ax + 2bx


= (2a)3 – (b)3 – 2x(2a – b)


We know, a3 – b3 = (a – b)(a2 + ab + b2)


= (2a – b) ((2a)2 + 2a.b + (b)2) – 2x(2a – b)


= (2a – b) (4a2 + 2ab + b2) – 2x(2a – b)


= (2a – b) (4a2 + 2ab + b2 – 2x)


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