Q3 of 65 Page 145

Short answer type questions:

Let us write the values of a and p if 2x2 + px + 6 = (2x– a) (x – 2) is an identity.

(2x– a) (x – 2) = 2x2 – 4x – ax + 2a


⇒ 2x2 –x(a + 4) + 2a


Since the above expression is identical to 2x2 + px + 6, therefore their coefficients can be equated.


⇒ 2a = 6


⇒ a =3


Also, p = -(a + 4) = -7


∴ The values of a and p are 3 and -7 respectively.


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