Q2 of 65 Page 145

If a2 – b2 = 11 × 9 and a & b are positive integers (a>b) then

Using the identity x2 – y2 = (x + y)(x – y)


(a + b)(a – b) = 11 × 9


Since 11 is a prime number therefore the factors can be equated,


a + b = 11


And a – b = 9


On solving above two equations we get,


a = 10 and b = 1

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