Q2 of 65 Page 145

If x2 – px + 12 = (x – 3) (x – a) is an identity, then the values of a and p are respectively.

(x – 3) (x – a) = x2 – (3 + a)x + 3a


⇒ 3a = 12


⇒ a = 4


Also, p = 3 + a


⇒ p = 3 + 4 = 7

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