Let us factorise the following algebraic expressions:
(x2 – x) y2 + y – (x2 + x)
The given expression can be rewritten as:
x(x – 1)y2 + x2y – (x2 – 1)y – x(x+1)
⇒ x2 – xy2 + x2y – x2y + y – x2 – x
As we know that a2 – b2 = (a + b)(a – b)
⇒ xy[(x – 1)y + x] – (x + 1)[(x – 1)y + x]
⇒ (xy – x - 1)(xy + x – y)
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