Let us factorise the following algebraic expressions:
(a + b)2 – 5a – 5b – 6
The given expression can be rewritten as:
(a + b)2 – 5(a + b) + 6
Assume (a + b) = p,
⇒ p2 – 5p+ 6
⇒ p2 – 2p - 3p + 6
⇒ p(p - 2) -3(p - 2)
⇒ (p – 3)(p – 2)
On substituting the value of p, we get,
(a +b - 3)(a + b – 2)
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