If
then the value of a3 + b3 is
The given equation on LCM reduces to:
a2 + b2 = ab
Also we know that,
a3 + b3 = (a + b)(a2 + b2 – ab)
On substituting the value of a2 + b2 in above equation, we get,
⇒ (a + b) (ab – ab)
⇒ 0
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