Q3 of 92 Page 71

Let us solve the following simultaneous equations by the method of comparison and check whether the solutions satisfy the equations.

2(x – y) = 3


5x + 8y = 14

Let’s express the variable in terms of another variable.

⇒ 2(x - y) = 3 ………[1]


⇒ 2x - 2y = 3


⇒ 2x = 3 + 2y


………[3]


and,


5x + 8y = 14 ………[2]


⇒ 5x = 14 – 8y


………[4]


on comparing eq. [3] and eq. [4]


we get,



⇒ 15 + 10y = 28 – 16y


⇒ 26y = 13


………[5]


from eq. [3]





………[6]


by eq. [5] and [6]


x = 2,


by using the result in eq. [1] and eq. [2]


2(x - y) = 3


L.H.S




= 3 = R.H.S


similarly,


by eq. [2]


5x + 8y = 14


L.H.S



= 10 + 4


= 14 = R.H.S


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Let us solve the following simultaneous equations by the method of comparison and check whether the solutions satisfy the equations.


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