Q5 of 92 Page 71

Let us solve the following simultaneous equations in two variables by the method of comparison:

2 – 2(3x – y) = 10


10(4 – y) – 5x = 4(y – x)

expressing the equations in terms of one variable

2 – 2(3x – y) = 10


2 – 6x + 2y = 10


6x = 2y – 8


dividing by 3 on both sides.


3x = y – 4


………[1]


10(4 – y) – 5x = 4(y – x)


40 – 10y – 5x = 4y – 4x


x + 14y = 40


x = 40 – 14y ………[2]


by comparing eq. [1] and eq. [2]



y – 4 = 120 – 42y


………[3]


by using [3] in [1]




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