Let us solve the following simultaneous equations in two variables by the method of comparison:
2 – 2(3x – y) = 10
10(4 – y) – 5x = 4(y – x)
expressing the equations in terms of one variable
2 – 2(3x – y) = 10
⇒ 2 – 6x + 2y = 10
⇒ 6x = 2y – 8
dividing by 3 on both sides.
⇒ 3x = y – 4
………[1]
10(4 – y) – 5x = 4(y – x)
⇒ 40 – 10y – 5x = 4y – 4x
⇒ x + 14y = 40
⇒ x = 40 – 14y ………[2]
by comparing eq. [1] and eq. [2]
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⇒ y – 4 = 120 – 42y
………[3]
by using [3] in [1]
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