Let us solve the following simultaneous equations in two variables by the method of substitution and check whether the solutions satisfy the equations.


Given
… (1)
And
… (2)
Expressing x of equation (1) in terms of y,
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⇒ x + y = 3xy
∴ x = 3xy – y … (3)
Substituting (3) in (2),
![]()
![]()
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⇒ 3xy – 2y = xy
⇒ 3xy – xy = 2y
⇒ 2xy = 2y
∴ x = 1
Substituting x value in (3),
⇒ x = 3xy – y
⇒ 1 = 3(1) y – y
⇒ 1 = 3y – y
⇒ 1 = 2y
∴ y = 1/2
∴ By solving, x = 1 and y = 1/2.
Justification:
(1) - ![]()


⇒ 3 = 3
And (2) - ![]()


⇒ 1 = 1
∴ We can see that x = 1 and y = 1/2 satisfy equations (1) and (2).
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