Q5 of 92 Page 73

Let us solve the following simultaneous equations in two variables by the method of substitution.


Given … (1)


And … (2)


Expressing x of equation (1) in terms of y,





… (3)


Substituting (3) in (2),






⇒ 21y – 15 = 6y


⇒ 21y – 6y = 15


⇒ 15y = 15


∴ y = 1


Substituting y value in (3),




∴ x = 1


∴ By solving, we get x = 1 and y = 1.


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