Solve the following equations by graphical method- 2x + 3y=8; 4x – 3/2y = 1
For solving these equations by the graphical method, we need to form separate tables for each equation.
We have the equations,
2x + 3y = 8 …(i)
…(ii)
Take equation (i), we have
2x + 3y = 8
We can write it as,
⇒ 3y = 8 – 2x
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Now, assign values of x and compute y.
We can assign values of x = …, -3, -2, -1, 0, 1, 2, 3, 4,…
It is not necessary to put all values. But to form an accurate graph, it is necessary to put atleast three values.
Say, we put x = 0.
Then, ![]()
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⇒ y = 2.67
We have, (0, 2.67).
Now, put x = 1.
Then, ![]()
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⇒ y = 2
We have, (1, 2).
Now, put x = 2.
Then, ![]()
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⇒ y = 1.33
We have, (2, 1.33).
Now, put x = 3.
Then, ![]()
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⇒ y = 0.67
We have, (3, 0.67).
We can further find out y by putting values of x = …,-5,-4,-3,…,6,7,… but here we have just put four values.
Record it in a table,

Now, take equation (ii),
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We can write it as,
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…(iv)
Assign values for x and compute it y.
For equation (iv):
Say, we put x = 0.
Then, ![]()
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⇒ y = -0.67
We have, (0, -0.67).
Now, put x = 1.
Then, ![]()
![]()
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⇒ y = 2
We have, (1, 2).
Now, put x = 2.
Then, ![]()
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⇒ y = 4.67
We have, (2, 4.67).
Now, put x = 3.
Then, ![]()
![]()
![]()
![]()
⇒ y = 7.33
We have, (3, 7.33).
Record it in a table.

Represent the two tables on a graph, we get

Notice the intersection point of these two lines, 2x + 3y = 8 and
.
These two lines intersect each other at (1, 2) in the 1st quadrant.
⇒ (1, 2) is the solution of these equations.
Thus, solution is x = 1 and y = 2.
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