Q1 of 102 Page 44

Solve the following equations by the method of elimination (by substitution)

2x + 3y = 9


3x + 4y = 5

We have,

2x + 3y = 9 …(i)


3x + 4y = 5 …(ii)


From equation (i),


2x + 3y = 9


2x = 9 – 3y


…(iii)


Substituting the value of x from equation (iii) in equation (ii), we get





27 – y = 10


y = 27 – 10


y = 17


Putting this value of y in equation (iii), we get





x = -21


Thus, we get the solution as x = -21 and y = 17.


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