Q6 of 102 Page 44

Solve the following equations by the method of elimination (by substitution)

5x – 2y = 19


3x + y = 18

We have

5x – 2y = 19 …(i)


3x + y = 18 …(ii)


From equation (i),


5x – 2y = 19


⇒ 5x = 2y + 19


…(iii)


Substituting the value of x from equation (iii) in equation (ii), we get





⇒ 6y + 57 + 5y = 90


⇒ (6y + 5y) + 57 = 90


⇒ 11y + 57 = 90


⇒ 11y = 90 – 57


⇒ 11y = 33



⇒ y = 3


Putting this value of y in equation (iii), we get





⇒ x = 5


Thus, we get the solution as x = 5 and y = 3.


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