Find the solution of the system of equations
2x + 3y = 9; 3x + 4y = 5
2x + 3y = 9 ……equation (i)
3x + 4y = 5 ……equation (ii)
Multiplying equation (i) by 3 and multiplying equation (ii) by 2 we get
6x + 9y = 27 ….equation (iii)
6x + 8y = 15 …..equation(iv)
Subtracting the above two equations we get
y = 12
⇒ 2x + 36 = 108
⇒ 2x = 72
⇒ x = 36
Answer: x = 36, y = 12
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