Q3 of 102 Page 44

Solve the following equations by the method of elimination (by substitution)

3x + 2y = 11


2x + 3y = 4

We have

3x + 2y = 11 …(i)


2x + 3y = 4 …(ii)


From equation (i),


3x + 2y = 11


3x = 11 – 2y


…(iii)


Substituting the value of x from equation (iii) in equation (ii), we get





22 – 4y + 9y = 12


22 + 5y = 12


5y = 12 – 22


5y = -10



y = -2


Putting this value of y in equation (iii), we get





x = 5


Thus, we get the solution as x = 5 and y = -2.


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