Solve the following equations by the method of elimination (by substitution)
x + 2y = -1
2x – 3y = 12
We have
x + 2y = -1 …(i)
2x – 3y = 12 …(ii)
From equation (i),
x + 2y = -1
⇒ x = -2y – 1 …(iii)
Substituting the value of x from equation (iii) in equation (ii), we get
2(-2y – 1) – 3y = 12
⇒ -4y – 2 – 3y = 12
⇒ -7y – 2 = 12
⇒ -7y = 2 + 12
⇒ -7y = 14
⇒ y = -2
Putting this value of y in equation (iii), we get
x = -2(-2) – 1
⇒ x = 4 – 1
⇒ x = 3
Thus, we get the solution as x = 3 and y = -2.
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