The length breadth and height of the cuboidal tank are 150cm, 120cm and 110cm respectively. The tank has 129600cm³ of water in it. 100 porous bricks each having dimensions 20cm × 10cm × 10cm and are placed in the tank. Calculate the raise in the water level of the tank. If each brick absorbs 1/10 of its own volume.

Given,

Dimensions of pool

length (L) = 150 cm

breadth (B) = 120 cm

height (H) = 110 cm

Volume of pool = L × B × H

= 150 × 120 × 110

= 1980000 cm³

Volume of water in tank = 129600 cm³

=

=

= 7.2

Dimensions of brick

length (l) = 20 cm

breadth (b) = 10 cm

height (h) = 10 cm

Volume of brick = l × b × h

= 20 × 10 × 10

= 2000 cm³

Water absorbed by brick = 0.10 (Volume of brick)

= 200 cm³

Water absorbed by 100 bricks = 100 (Water absorbed by brick)

= 20000 cm³

Remaining water in tank = 129600 cm³ - 20000 cm³

= 109600

Volume of 100 bricks = 100(2000)

= 200000

Net volume = Remaining water in tank

+

Volume of 100 bricks

= 109600 + 200000

= 309600

=

=

= 17.2

Rise in height of water = 17.2 – 7.2

= 10

So, the raised water level of the tank is 10cm