A rectangular room is a 6m long, 4.8m wide and 3.5m high. Find the inner surface area of the four walls.
Given,
length (l) = 6 m
width (w) = 4.8 m
height (h) = 3.5 m
Total area of walls = 2(wh) + 2(lh)
= 2h (l+w)
= 2 × 3.5 (4.8 + 6)
= 75.6 m2
So, the inner surface area of walls is 75.6 m2
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