In AABC, hypotenuse AC = 12 cm and ∠A = 60°, then find the length of remaining sides.
Drawing the triangle for better reference of the problem.

Here we are actually sure that B is the 90 degrees angle as the ends of the hypotenuse can never have 90 degrees.
Also, when the ends are produced backwards (where angle A is produced backwards at an angle of 60 degrees) they seem to form a 90 degree angle.
The remaining sides length can be figured out by simple trigonometry,
Using ![]()
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⇒ ![]()
or, AB = 6cm.
Now, using ![]()
⇒ ![]()
or, BC= ![]()
= 6√3 cm.
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