Q14 of 68 Page 9

An observer 1.75 m tall is at a distance of 24 m from a wall 25.75 m high. Find the angle of elevation of the top of the wall at the observer's eye.

Drawing a diagram for a better perspective of the problem,



We know that from trigonometric ratios that,



The angle of elevation of top of the wall will be ∠ABC.


Now Let ∠ABC = θ


Therefore,



From the figure we can see that,


AC = BC = 24 m.


Therefore,



θ = arctan(1)


θ =45°


Therefore, the angle of elevation of the top of the wall from the eyes of the observer is .


More from this chapter

All 68 →
12

The length of the shadow of a high bamboo tree is 3m, then what will be the angle of elevation of the top of the bamboo tree at the end of the shadow.

 13

The height of a telephone pole is times the length of its shadow, then find the angle of elevation of the source of light.

 15

A tower stands vertically on the ground. At a point on the ground, 15 m away from the foot of the tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?

 16

At a point 20 m away from the foot of a tower, the angle of elevation of the top of the tower is 30°. Find the height of the tower.