The upper part of a tree is broken over by the strong wind makes an angle of 30° with the ground. The top of the broken tree meets the ground at a distance of 25 m from the foot of the tree. Find the original height of the tree.

Let in ∆ABC,
AB broken part the of Tree
AC unbroken part of the Tree
BC the distance between root and the top of the Tree
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Now, ![]()
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So, Height of the Tree ![]()
Therefore, the height of the tree is 51.96 m.
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