An idol 30m tall stands on a pillar 15 m high. Find the angle in degrees which the idol subtends at a point distant
m from the base of the pillar.

Let AB be the idol and BC be the pillar
So, AB = 30 m
and BC = 15 m
Distance from the base of pillar = 15√3 m
Now, In right ΔACD, we have
![]()
![]()
![]()
![]()
![]()
⇒ tan x = tan 30°
⇒ x = 30°
Hence, the angle subtends from the base of the pillar is 30°
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.