The angle of elevation of an airplane from a point A on the ground is 60° after a flight of 30 seconds, the angle of elevation changes to 30°. If the plane is flying at a constant height of 3600
m, find the speed, in km/hour, of the plane.

Let us suppose that DE = x and CD = y
Now, In right ΔBED, we have
![]()
![]()
⇒ x = 3600
In right ΔACE, we have
![]()

⇒ CE = 10800
⇒ CD + DE = 10800
⇒ y + x = 10800
⇒ y + 3600 = 10800
⇒ y = 10800 – 3600
⇒ y = 7200
∵ AB = CD = 7200
We know that,
![]()
![]()
![]()
Hence, the speed of the aeroplane is 864 km/hr
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

