The pilot of helicopter at an altitude of 1000 m sees two aeroplanes, one on his left and the other on his right at the same height and finds their angles of depression as 45° and 60°. Find the distance between the two aeroplanes.

From the ∆ADC,
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From the ∆DBC,
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So, Distance between the two aeroplanes = AD +DB
= x + y = 1000+577.4
= 1577.4 m
Therefore, the distance between the two aeroplanes is 1577.4 m.
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