Q28 of 68 Page 9

A man of height 1 .5 m sees the top of a tree and the angle of elevation of the top at his eye is 60°. Find the height of the tree if the distance of the man from the tree is 36 m.

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Here distance of the man from tree is given


BC = DE = 36 m


And height of man = BD = CE =1.5 m


From the ∆ABC,





Now, height of the tree = AC + CE


= 62.35 + 1.5


= 63.85


Therefore, height of the tree is 63.85 m.


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