Q13 of 68 Page 9

The height of a telephone pole is times the length of its shadow, then find the angle of elevation of the source of light.


We have to measure the angle of elevation of the source of light from the end of the bamboo tree with the horizontal line as the reference.


i,e; We have to find ∠ LCM


But from the diagram it is clear that, ∠LCM = ∠ACB


Now, using trigonometric ratios,






Θ = 30°


Therefore, the angle of elevation of the source of light is 30°.


More from this chapter

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11

AB is a vertical wall and B is on the ground. The ladder AC is resting at C on the ground. ∠ACB = 45°, BC = 5m, find the length of the ladder.

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The length of the shadow of a high bamboo tree is 3m, then what will be the angle of elevation of the top of the bamboo tree at the end of the shadow.

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An observer 1.75 m tall is at a distance of 24 m from a wall 25.75 m high. Find the angle of elevation of the top of the wall at the observer's eye.

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