Q41 of 68 Page 9

Two men are on the opposite sides of a tower. They measure the angles of elevation of the tower as 25° and 40° respectively. If the height of the tower is 35 m, find the distance between two men; having given tan 25° = 0.4663 and tan 40° = 0.8391.


In right Δ ABP, we have






⇒ x = 75.058 m


⇒ x = 75.06


In the right Δ ABQ, we have





⇒ y = 41.71 m


So, the distance between two men = x + y


= 75.06 + 41.71


= 116.77 m (approx.)


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