In fig 3.28 the circles with centres A and B touch each other at E. Line is a common tangent which touches the circles at C and D respectively. Find the length of seg CD if the radii Fig. 3.28 of the circles are 4 cm, 6 cm.


Given that two circles with centre A and B touch each other externally. We know that if the circles touch each other externally, distance between their centres is equal to the sum of their radii.
⇒AB = (4 + 6) cm = 10 cm
In ∆ABC right-angles at A,
BC2 = CA2 + AB2 {Using Pythagoras theorem}
⇒BC2 = 42 + 102
⇒BC2 = 16 + 100
⇒ BC = √116 cm
In ∆DBC,
∠ BDC = 90° because D is the point of contact of tangent CD to circle centred B
BC2 = CD2 + DB2 {Using Pythagoras theorem}
⇒CD2 = 116 - 62
⇒CD2 = 116 - 36
⇒ CD = √80 cm = 4√5
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