In figure 3.88, circles with centres X and Y touch internally at point Z. Seg BZ is a chord of bigger circle and intersects smaller circle at point A. Prove that, seg AX || seg BY.

XA and YB are the radii of the respective circles.
AZ and BZ are the chords of the circles.
In triangle XAZ,
AX = XZ {Radii of the same circle}
⇒ ∠ XAZ = ∠ XZA {angles opposite to equal sides are equal}
In triangle YBZ,
YB = YZ {Radii of the same circle}
⇒ ∠ YBZ = ∠ YZB {angles opposite to equal sides are equal}
⇒ ∠ XAZ = ∠ XZA = ∠ YBZ = ∠ YZB
∵ Corresponding angles are equal
⇒ XA||YB
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