Q14 of 59 Page 83

In figure 3.92, O is the centre of a circle, chord PQ chord RS If POR = 70°and (arc RS) = 80°, find -

(1) m(arc PR)


(2) m(arc QS)


(3) m(arc QSR)



(1) m(arc PR) = POR = 70°


(2) POQ + QOS + ROS + POR = 360°


As PQ = RS, POQ = ROS = 80°


POQ + QOS + ROS + POR = 360°


80 + QOS + 80 + 70 = 360


230 + QOS = 360


QOS = 130°


m(arc QS) = QOS = 130°


(3) m(arc QSR) = QOS + ROS = 130 + 80 = 210°


More from this chapter

All 59 →