In figure 3.92, O is the centre of a circle, chord PQ ≅ chord RS If∠ POR = 70°and (arc RS) = 80°, find -
(1) m(arc PR)
(2) m(arc QS)
(3) m(arc QSR)

(1) m(arc PR) = ∠POR = 70°
(2) ∠POQ + ∠ QOS + ∠ROS + ∠POR = 360°
As PQ = RS, ∠ POQ = ∠ROS = 80°
⇒ ∠POQ + ∠ QOS + ∠ROS + ∠POR = 360°
⇒ 80 + ∠QOS + 80 + ∠ 70 = 360
⇒ 230 + ∠ QOS = 360
⇒ ∠QOS = 130°
m(arc QS) = ∠QOS = 130°
(3) m(arc QSR) = ∠QOS + ∠ROS = 130 + 80 = 210°
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