Q18 of 59 Page 83

In figure 3.96 P is the point of contact.

(1) If m(arc PR) = 140°, POR = 36°,find m(arc PQ)


(2) If OP = 7.2, OQ = 3.2,find OR and QR


(3) If OP = 7.2, OR = 16.2,find QR.



(1)Given: m(arc PR) = 140°, POR = 36°


ROP is an external angle.



m(arc PQ) = 140° -2 × 36°


m(arc PQ) = 68°


(2)Given: OP = 7.2, OQ = 3.2


Here, RO × OQ = OP2


RO × 3.2 = 7.2 × 7.2


RO = 16.2


QR = RO – OQ = 16.2 – 3.2 = 13


(3) Given: OP = 7.2, OR = 16.2


Here, RO × OQ = OP2


16.2 × OQ = 7.2 × 7.2


OQ = 3.2


QR = RO – OQ = 16.2 – 3.2 = 13


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