Q19 of 59 Page 83

In figure 3.97, circles with centres C and D touch internally at point E. D lies on the inner circle. Chord EB of the outer circle intersects inner circle at point A. Prove that, seg EA seg AB.



We see that the line joining D to E passes through C.


In the smaller circle,


A lies in the semicircle,


EAD = 90°


DA is perpendicular on the chord EB of the bigger circle.


We know that perpendicular from the center bisects the chord.


Therefore, EA = AB.


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