In figure 3.79, O is the centre of the circle and B is a point of contact. seg OE
seg AD, AB = 12, AC = 8, find

(1) AD
(2) DC
(3) DE.
(1)Given: OE
AD, AB = 12, AC = 8
⇒ AD × AC = AB2
This property is known as tangent secant segments theorem.
⇒ AD × 8 = 122
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(2)DC = AD – AC = 18 – 8 = 10
(3)As we know that a perpendicular from centre divides the chord in two equal parts. Here, OE
AD.
⇒ DE = EC
⇒ DE + EC = DC
⇒2DE = DC
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