Q3 of 59 Page 82

In figure 3.79, O is the centre of the circle and B is a point of contact. seg OE seg AD, AB = 12, AC = 8, find


(1) AD


(2) DC


(3) DE.


(1)Given: OE AD, AB = 12, AC = 8


AD × AC = AB2


This property is known as tangent secant segments theorem.


AD × 8 = 122



(2)DC = AD – AC = 18 – 8 = 10


(3)As we know that a perpendicular from centre divides the chord in two equal parts. Here, OE AD.


DE = EC


DE + EC = DC


2DE = DC



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