In figure 3.86, circle with centre M touches the circle with centre N at point T. Radius RM touches the smaller circle at S. Radii of circles are 9 cm and 2.5 cm. Find the answers to the following questions hence find the ratio MS:SR.
(1) Find the length of segment MT
(2) Find the length of seg MN
(3) Find the measure of ∠ NSM.

(1)MT = radius of the big circle = 9 cm
(2)MN = MT – TN = 9 – 2.5 = 6.5 cm
(3)SM is the tangent to the circle with radius 2.5 cm with S being point of contact.
∠ NSM = 90° Using tangent-radius theorem which states that a tangent at any point of a circle is perpendicular to the radius at the point of contact.
In ∆MSN,
∠ MSN = 90°{∵ MS is the tangent to the small circle with point of contact S}
⇒ MN2 = MS2 + NS2
MS2 = MN2 – NS2
⇒ MS2 = 6.52 – 2.52
⇒ MS2 = 36
⇒ MS = 6 cm
Now, SR = MR – MS = 9 – 6 = 3 cm
⇒ MS:SR = 6:3 = 2:1
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