Q3 of 59 Page 63

In fig 3.39 chord AB chord CD, Prove that, arc AC arc BD


chord AB chord CD


m(arc AB) = m(arc CD){Corresponding arcs of congruent chords of a circle (or congruent circles) are congruent}


Subtract m(arc CB) from above,


m(arc AB)– m(arc CB) = m(arc CD) – m(arc CB)


m(arc AC) = m(arc BD)


arc AC arc BD


Hence, proved.


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