In figure 3.99, seg MN is a chord of a circle with centre O. MN = 25,L is a point on chord MN such that ML = 9 and d(O,L) = 5.
Find the radius of the circle.

The figure is shown below:

Draw perpendicular on MN from the center O.
Mark the point as A. Join O to N.
As we know that perpendicular on a chord bisects the chord.
AM = MN/2
⇒ AM = 25/2 = 12.5
Given that LM = 9
⇒ LM + LA = AM
⇒ 9 + LA = 12.5
⇒ LA = 3.5
In Δ OAL,
⇒ OL2 = OA2 + AL2
⇒ 52 = OA2 + (3.5)2
⇒ OA2 = 25-12.25
⇒ OA2 = 12.75
In Δ OAN,
⇒ ON2 = OA2 + AN2
⇒ ON2 = 12.75 + (12.5)2
⇒ ON2 = 12.75 + 156.25
⇒ ON2 = 169
⇒ ON = 13
Therefore, the radius of the circle is 13.
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